Wire Size Calculator — AWG, mm² & Voltage Drop for DC and AC Circuits

If you undersize wire, you’re setting yourself up for voltage drop and reliability problems—especially in low-voltage DC circuits. For mains, a 2V drop out of 120V barely matters. But on a 12V actuator feed, that’s over 16% loss, enough to slow or stall a load. The calculator below lets you work out conductor gauge, cross-sectional area, and voltage drop based on voltage, current, one-way length, and allowed drop. It covers DC, single-phase AC, and three-phase systems, and you’ll find step-by-step formulas, a temperature correction guide, a marine example, and practical answers to real wire sizing problems.

Size wire for the worst case: peak current, maximum expected temperature, and the longest cable run. Problems almost always appear when design assumptions get optimistic.

"A 2V drop on a 120V circuit is a rounding error. The same 2V on a 12V actuator feed is 16.7% — enough to stall the motor under load. Low-voltage DC is where wire sizing actually matters, and where most field mistakes happen." — Robbie Dickson, FIRGELLI Automations founder and former Rolls-Royce, BMW, and Ford engineer

What is wire sizing?

Wire sizing means picking a conductor large enough that voltage drop stays within limits and currents don’t cause excessive heating. Too small a wire causes excessive resistance, so your load won't see full supply voltage and the wire itself wastes power as heat.

How does wire sizing work in plain terms?

If you think of wire like a pipe: smaller pipes have more pressure loss for a given flow, and longer pipes multiply the problem. It's the same with wire—higher current and longer distance both demand larger cross-sectional area. This calculator works out the minimum area so the voltage drop isn’t excessive at the load end.

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What does a wire-sizing circuit look like?

Wire Size — DC / Single-Phase AC Circuit V source + Load V_load L = one-way cable length (m) I → ← I return Area = A mm² | Diameter = d | Material: Cu / Al V_drop = (I × ρ × 2L) / A [DC / Single-phase] Temp correction: ρ₂ = ρ₁ × (1 + α × (T₂ − 20°C)) | Three-phase: V_drop = (√3 × I × ρ × L) / A

Wire Size Calculator

How do you use this wire size calculator?

Engineering calculation notice

This calculator is intended for education, concept evaluation, and preliminary design. Results are based on the equations and assumptions described on this page, but cannot account for every real-world load case, tolerance, material property, environmental condition, installation detail, safety factor, code, or regulatory requirement. Verify all inputs, assumptions, units, and results independently before selecting components or using the result in a real application. Safety-critical, structural, medical, lifting, transportation, or regulated applications must be reviewed by a qualified engineer.

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  1. Select your Calculation Mode, electrical system (DC/single-phase or three-phase), conductor material (copper or aluminum), and maximum operating temperature.
  2. Enter your source voltage, current draw (use peak or maximum for worst-case sizing), and one-way cable length in metres — the calculator handles the round-trip factor automatically.
  3. Set your allowable voltage drop as a percentage (NEC recommends 3% for motors and actuators) or as an absolute voltage value depending on the selected mode.
  4. Click Calculate to see your result.
Reference = 20°C; enter maximum expected temperature
e.g. 12, 24, 48, 120, 240 V
NEC recommends max 3–5%; use 3% for motors & actuators
Use peak / maximum current for worst-case sizing
Source to load, one direction only — calculator doubles it

Wire Size Calculator Interactive Visualizer

This layout shows how increasing wire length increases voltage drop, and, in contrast, using a bigger wire gauge helps keep voltage drop and power waste in check. Track calculations for required AWG size, area, and losses in real time as you vary the slider controls.

Source Voltage 12V
Current Draw 20A
Cable Run Length 5m
Max Voltage Drop 3%

REQUIRED AWG

10 AWG

WIRE AREA

5.26 mm²

VOLTAGE DROP

0.32V

POWER LOSS

6.4W

FIRGELLI Automations — Interactive Engineering Calculators

What equations does the wire size calculator use?

What does a simple wire-sizing example look like?

A 12V DC actuator draws 20A and is located 5m from the power supply. Maximum allowable voltage drop is 3% (0.36V). Using copper at 25°C:

A = (20 × 1.685×10⁻⁸ × 2 × 5) / 0.36 = 4.68 mm²

Next standard size up: 10 AWG (5.261 mm²). Actual voltage drop with 10 AWG: 0.321V (2.67%). Within limit. ✓

Wire Cross-Sectional Area — DC / Single-Phase AC

Use the formula below to calculate required wire cross-sectional area for DC and single-phase AC circuits.

A = (I × ρ × 2L) / Vdrop

A = Required cross-sectional area (m²; multiply by 10⁶ for mm²)

I = Peak current (A)

ρ = Resistivity of conductor at operating temperature (Ω·m)

L = One-way cable length (m) — factor of 2 accounts for return conductor

Vdrop = Allowable voltage drop = Vsource × (drop% / 100)

Wire Cross-Sectional Area — Three-Phase AC

Use the formula below to calculate required wire cross-sectional area for three-phase AC circuits.

A = (√3 × I × ρ × L) / Vdrop

The factor of 2 disappears because three-phase systems have no dedicated return conductor. The √3 factor converts between phase current and line current. Vdrop here refers to the line-to-line voltage drop.

Temperature Correction of Resistivity

Use the formula below to calculate temperature-corrected resistivity before applying it to wire sizing.

ρ₂ = ρ₁ × (1 + α × (T₂ − T₁))

ρ₁ = Resistivity at reference temperature T₁ = 20°C

α = Temperature coefficient: Copper = 0.00404 /°C, Aluminum = 0.00403 /°C

T₂ = Maximum expected operating temperature (°C)

Copper at 20°C: ρ = 1.68×10⁻⁸ Ω·m | Aluminum at 20°C: ρ = 2.82×10⁻⁸ Ω·m

Area Unit Conversions

Use the formula below to calculate kcmil from mm².

kcmil = mm² / 0.5067

1 circular mil (cmil) = area of a circle with 1 mil (0.0254 mm) diameter = 5.067×10⁻⁴ mm²

1 kcmil = 1000 cmil = 0.5067 mm²

AWG diameter formula: dn = 0.005 × 92(36−n)/39 inches, where n = AWG number (per ASTM B258, Standard Specification for Standard Nominal Diameters and Cross-Sectional Areas of AWG Sizes).

What is the engineering theory behind wire sizing?

Why does voltage drop matter more in low-voltage DC?

Every wire has resistance: R = ρL/A. When current flows, Ohm’s Law (V = IR) ensures some voltage gets lost before the load. In household mains (120–240V) a 2V drop is minor—hardly anything percentage-wise. But on 12V or 24V systems, that same 2V can cripple a motor or actuator, which is why DC work demands conservative wire sizing. NEC’s 3% guideline is there for a good reason—ignore it and you’ll get unreliable equipment and nuisance problems.

Resistance depends on four things: material (copper or aluminum), length, area, and temperature. The AWG scale isn’t linear—three sizes thicker is double the area, and cuts resistance in half. So if a 16 AWG run is marginal on length, jumping to 13 AWG makes a significant improvement, and 10 AWG is another big jump again.

How does temperature change wire resistivity?

For copper, every degree above 20°C means resistivity goes up by about 0.4%. At typical wire temperatures (like 75°C on a fully-loaded circuit in conduit), that’s 22% extra resistance—and 22% more voltage drop for the same run. If you’re working in a hot engine bay, or running heavy current in a tight bundle, assume real wire temp could be 20–30°C above ambient. Do the calculation at the max operating temp you actually expect; don’t cheat. Aluminum behaves much the same with temperature but starts worse: its base resistivity is 68% higher than copper, so you always need to upsize it by about two AWG compared to copper. Its low density means it’s light—great for long spans and aircraft, but less useful in automotive or marine where vibration and connections are issues.

Why does DC wire sizing use a factor of 2?

Current always has to return to where it came from. So for every metre of supply wire, there’s the same resistance in the return. If your actuator is 8 metres from the battery, resistance is for 16 metres total. Forgetting the “2L” is a classic mistake. Some people enter round-trip distance and some calculators double the one-way. Be sure which convention you’re following—using half the resistance gives you half the correct conductor area and twice the voltage drop you expected, especially in low-voltage work. Only three-phase is different, since there’s no separate return—just three phase wires sharing current.

Worked Example: Marine 24V DC Winch Installation

Suppose you’re running a 24V electric windlass drawing 38A on a 38-foot sailboat. Battery to windlass is 14.7 m one-way. Use copper in conduit, expect 45°C temp, and stick to 3% voltage drop. Here's how you work it out:

Step 1: Temperature-corrected resistivity

ρ = 1.68×10⁻⁸ × (1 + 0.00404 × (45 − 20))
ρ = 1.68×10⁻⁸ × (1 + 0.101)
ρ = 1.68×10⁻⁸ × 1.101
ρ = 1.850×10⁻⁸ Ω·m

Step 2: Allowable voltage drop

V_drop = 24V × 0.03 = 0.720 V

Step 3: Required cross-sectional area at 45°C

A = (38 × 1.850×10⁻⁸ × 2 × 14.7) / 0.720
A = (38 × 1.850×10⁻⁸ × 29.4) / 0.720
A = 2.065×10⁻⁵ / 0.720
A = 2.868×10⁻⁵ m² = 28.68 mm² = 56.6 kcmil

Step 4: Select next standard AWG size up

28.68 mm² exceeds 3 AWG (26.67 mm²), so next size up is 2 AWG at 33.63 mm².

Step 5: Verify actual voltage drop with 2 AWG

V_drop = (38 × 1.850×10⁻⁸ × 29.4) / (33.63×10⁻⁶)
V_drop = 2.065×10⁻⁵ / 33.63×10⁻⁶ = 0.614 V = 2.56% ✓ (below 3% limit)

Step 6: What would happen without temperature correction?

Using ρ at 20°C: A = (38 × 1.68×10⁻⁸ × 29.4) / 0.720 = 26.07 mm² → selects 3 AWG (26.67 mm²)
Actual voltage drop at 45°C with 3 AWG: V_drop = 2.065×10⁻⁵ / (26.67×10⁻⁶) = 0.774 V = 3.23% ✗

If you skip temperature correction, you’ll undersize. That might not show up at the dock, but will when you winch in hot weather after hours at anchor.

How is three-phase wire sizing different?

Three-phase circuits never return through a separate neutral—currents sum to zero, so there’s no need to double the length in resistance calculations. Use A = (√3 × I × ρ × L) / V_drop. The √3 comes from phase geometry, not magic. This approach is more efficient for high-power runs, one reason it’s used in industrial settings—the same amount of copper moves more power at the same loss percentage.

What is special about wire sizing for linear actuators?

Actuators aren’t constant loads. They can draw as little as 2–4A in free run, but spike much higher (10–20A, sometimes more) at stroke end or if jammed. Wire sizing should always use maximum possible current, not just running load, or you risk voltage drop or nuisance tripping. If you’re using control boards with feedback (Hall or optical encoders), the feedback wires don’t need heavy gauge but do need to be isolated from noise. If you run feedback in the same cable as the power wires, you can get noise pickup. Use shielded cable or run signal wires separately, especially on long runs. The actuation won’t slow down with a little signal drop, but position feedback might glitch outright.

AWG ↔ mm² ↔ kcmil ↔ Diameter reference table

The values below are the standard wire sizes used by the calculator. kcmil is computed as mm² / 0.5067 per the article's conversion formula.

AWG mm² kcmil Diameter (mm)
28 AWG 0.0804 0.159 0.321
26 AWG 0.128 0.253 0.405
24 AWG 0.205 0.405 0.511
22 AWG 0.326 0.643 0.644
20 AWG 0.519 1.024 0.812
18 AWG 0.823 1.624 1.024
16 AWG 1.310 2.585 1.291
14 AWG 2.081 4.107 1.628
12 AWG 3.309 6.530 2.053
10 AWG 5.261 10.383 2.588
8 AWG 8.366 16.510 3.264
6 AWG 13.30 26.250 4.115
4 AWG 21.15 41.740 5.189
2 AWG 33.63 66.370 6.544
1/0 AWG 53.49 105.560 8.252
2/0 AWG 67.43 133.080 9.266
4/0 AWG 107.2 211.564 11.68
250 kcmil 126.7 250 12.70
500 kcmil 253.4 500 17.96

What are common mistakes when using this calculator?

  1. Forgetting the round-trip factor on DC and single-phase circuits. The "one-way cable length" input expects the source-to-load distance only — the calculator doubles it internally. Entering total round-trip length doubles the conductor area unnecessarily; entering one-way length on a calculator that doesn't double it underestimates voltage drop by 50%.
  2. Skipping temperature correction. The 20°C reference resistivity does not represent real operating conditions. Engine compartments, marine engine rooms, and conduit bundles routinely run 40–60°C; a loaded wire can self-heat another 20–30°C above ambient. Enter the maximum expected wire temperature, not ambient.
  3. Using running current instead of peak current for actuators and motors. Stall current on a 12V actuator can reach 10–20A while running current is only 2–4A. Size for the worst-case load, not the average.
  4. Using one-way length with the three-phase formula. Three-phase already removes the factor of 2 because there is no return conductor. Switching to three-phase mode after entering DC data, without rechecking, gives an undersized wire.
  5. Treating the recommended AWG as a hard answer. The calculator returns the next standard size up that satisfies voltage drop — it does not check ampacity, conduit fill, insulation temperature rating, or fuse coordination. Local code (NEC Article 310, Conductors for General Wiring — ampacity tables) governs the final selection.

How can you verify the calculator output is reasonable?

  1. Apply the three-gauge rule of thumb. Every three-gauge reduction doubles the cross-sectional area and halves the resistance. If doubling your current pushes the result from 14 AWG to 11 AWG (i.e. ~3 gauges thicker), the math is internally consistent.
  2. Check the copper-to-aluminum offset. Switching the material from copper to aluminum at the same current, length, voltage, and drop should bump the recommendation by roughly two AWG sizes. If it jumps by five or stays the same, an input is wrong.
  3. Cross-check against the metric ↔ AWG equivalents. 2.5 mm² ≈ 14 AWG, 4 mm² ≈ 12 AWG, 6 mm² ≈ 10 AWG, 10 mm² ≈ 8 AWG. If the calculator returns 6 mm² and 8 AWG together, something is off.
  4. Spot-check the percentage. A 12V system with 3% allowable drop has only 0.36V of margin. If the calculator returns a voltage drop near 1V on a 12V system, you have entered 24V drop tolerance against 12V supply, or used a 10× current.
  5. Run a back-calculation in Voltage Drop mode using the recommended AWG. The result should fall just under your target drop percentage — usually between 60% and 100% of the limit. If it returns 5% on a "3% target" run, recheck the inputs.

Industries: Marine (anchor windlass and house battery distribution), Automotive (wiring harnesses, 12V/24V accessory feeds), Industrial (three-phase power distribution above ~5 kW), Linear Actuator Systems (12V/24V DC motion control).
Mechanisms: DC power distribution, single-phase AC, three-phase AC, temperature-derated conductors, voltage-drop-limited cable runs.

Frequently Asked Questions

Q1: Why does the wire size formula multiply one-way length by 2?
Q2: What voltage drop percentage should I use for my application?
Q3: When should I choose aluminum wire over copper?
Q4: How does temperature affect wire sizing, and when does it matter?
Q5: What is the difference between AWG, kcmil, and mm², and how do I convert between them?
Q6: Does wire sizing for AC differ from DC at the same current and voltage?

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About the Author

Robbie Dickson — Chief Engineer & Founder, FIRGELLI Automations

Robbie Dickson brings over two decades of engineering expertise to FIRGELLI Automations. With a distinguished career at Rolls-Royce, BMW, and Ford, he has deep expertise in mechanical systems, actuator technology, and precision engineering.

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