Milk Cooler: Product Heat Removal

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A milk cooler transfers heat from milk through a refrigerated tank surface. Calculate the ideal heat removed from a batch using its volume, density, specific heat and temperature change.

Milk Product Heat-Removal Calculator

Enter milk volume, inlet and target temperatures, cooling time, density and specific heat. The worksheet computes only ideal product sensible heat and its time-average rate; it does not size a compressor or certify food-safety compliance.

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Entered milk mass
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Temperature drop
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Ideal product heat
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Average product load
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Equation Used

m=rho V; Q=m cp (Tin-Tout); Pavg=Q/t
The calculation covers ideal sensible heat removed from the entered milk mass. Tank heat gain, new warm inflow, agitator heat, ice/refrigerant storage, cycling, fouling, defrost and equipment efficiency are excluded.
  • Milk is represented by entered constant density and specific heat.
  • The entered batch has a uniform inlet and final temperature.
  • Cooling time is an averaging interval, not a guaranteed pull-down time.
  • Use applicable dairy regulations and qualified refrigeration design for real equipment.

The product heat load depends on milk mass and temperature drop. Equipment selection also requires the cooling conditions, additional heat gains and refrigeration-system performance.

Refrigerated tank and product circulation

A modern bulk tank commonly uses direct expansion at a tank surface: refrigerant evaporates while heat crosses the stainless-steel wall from the milk. Agitation promotes temperature uniformity and must be treated as part of the exact hygienic equipment design.

The animation traces product heat leaving the milk; it does not simulate refrigerant pressures, compressor cycling or biological safety.

Product-side heat removal

Use the worksheet to check the ideal sensible heat associated with an entered milk batch and temperature change. It is not a refrigeration-equipment selection, compliance calculation or operating instruction.

Ideal sensible-heat balance

m=rho V; Q=m cp (Tin-Tout); Pavg=Q/t

Q is reported in kWh after converting entered kJ/kg K. Pavg is only Q divided by the entered duration, not required compressor electrical power or refrigeration capacity. A target at or above the inlet temperature returns zero cooling load; heating is not modeled.

Product-load example

For 3,000 L at 1,020 kg/m3, cp=3.95 kJ/kg K, cooling from 35 C to 4 C, the ideal product heat is about 104.0 kWh. Spread uniformly over two hours, that product-side average is about 52.0 kW.

What refrigeration equipment selection requires

Real selection depends on heat gains, milk arrival profile, evaporating and condensing conditions, refrigerant circuit, storage, control strategy, cleaning, ambient conditions and qualified equipment data.

Milk-cooling questions

Does average product kW equal compressor input?

No. It is ideal heat removed from the milk per entered time.

Does the result prove a regulatory cooling time?

No. Compliance requires the applicable jurisdiction, equipment and measured process.

Why enter density and specific heat?

Density converts volume into mass, and specific heat relates that mass and temperature change to the heat removed.

Dairy and regulatory references

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