This calculator converts entered pressure and circular ram bore into ideal gross piston force, a force-equivalent mass under standard gravity, full-bore area and swept oil volume per millimetre. It does not rate a lift or safe load.
Hydraulic Lift Interactive Calculator
Explore ideal static pressure-area force and full-bore swept-volume conversions.
Equation Used
- Entered pressure acts uniformly on the full ram area, with no opposing chamber pressure included.
- Standard gravity g0=9.80665 m/s² is used only for force-equivalent mass conversion.
- Oil-per-mm is geometric swept volume for one millimetre of full-bore travel.
- No rod side, backpressure, friction, leakage, dynamics, strength, buckling, mounts, platform, stability, synchronization, valves, hoses, relief, controls or safety model.
The kilogram output is force divided by standard gravity, not allowable lifted mass. Real capacity requires pressure ratings, friction, backpressure, load geometry, stability, structure, redundancy and applicable lift-safety rules.
Ideal pressure-area and swept-volume model
Uniform differential pressure P over circular full-bore area A=pi d²/4 gives ideal gross force F=PA. Moving that full-bore piston one millimetre displaces volume A×0.001 m.
The diagram is qualitative and does not represent a rated lifting machine.
Use as a first-principles conversion
The results can check pressure-area force and swept-volume arithmetic. They cannot establish safe working load, speed, stroke, stability or component suitability.
Force, equivalent mass and volume
Pressure in bar is converted with 1 bar=100,000 Pa. Force-equivalent mass is F/g0 using standard gravity; it is not a load rating. Swept volume per millimetre is reported in mL/mm from the same circular area.
Worked force and volume example
For a 50 mm bore at 150 bar, area is 19.635 cm² and ideal gross force is about 29.45 kN. Dividing that force by standard gravity gives a 3,003 kg force-equivalent mass. Geometric swept volume is 1.963 mL per millimetre.
Scope and limitations
A real lift requires verified cylinder and component ratings, rod and wall strength, buckling and side load, seals and leakage, backpressure and losses, mounts and frame, load centre and stability, guide geometry, synchronization, hose-failure protection, check/counterbalance valves, mechanical locks, end stops, controls, inspection and applicable machinery and lifting regulations.
Questions
Is the kilogram result safe lifting capacity?
No. It is only ideal force divided by standard gravity.
Does oil per millimetre determine speed?
No. Speed additionally requires actual flow and leakage.
Does this include rod-side force?
No. It uses full-bore area only.
Calculation basis
The full circular area is A = πd²/4, and uniform pressure over that area gives ideal force F = PA. The calculator converts bar to pascals and millimetres to metres before evaluating force.
Dividing force by standard gravity gives its mass equivalent. Sweeping the same area through one millimetre gives A × 0.001 m of volume, converted to millilitres. These are force and geometry conversions; available flow, friction, opposing pressure and the lift structure must be assessed separately.
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