Electrical Resistance Unit Converter + Reference Table & Applications
You're reading a MOSFET datasheet and the RDS(on) is listed in milliohms. Your insulation tester reads in megohms. The wire resistance chart gives you ohms per thousand feet. You need to compare these values — and you need to do it fast without second-guessing decimal places. This converter handles every resistance unit from milliohms to gigaohms instantly. Below you'll find the live tool, a logarithmic reference diagram, worked examples, and practical guidance for actuator and motion control applications.
What Is Electrical Resistance?
Electrical resistance measures how much a component opposes the flow of current. We express it in ohms (Ω), but real-world values span from thousandths of an ohm to billions of ohms — so we use prefixed units like mΩ, kΩ, MΩ, and GΩ to keep numbers manageable.
Simple Explanation
Think of resistance like the diameter of a pipe. A wide pipe lets water flow easily — that's low resistance, measured in milliohms. A narrow pipe restricts flow — that's high resistance, measured in kilohms or megohms. Converting between resistance units is just shifting the decimal point by factors of 1,000. A 1 kΩ resistor is exactly 1,000 Ω, and a 1 MΩ resistor is 1,000,000 Ω.
Electrical Resistance Unit Converter
Converted Values
🎥 Video — Electrical Resistance Unit Converter
How to Use This Calculator
The converter updates instantly — no button to press. Here's the workflow:
- Enter your resistance value in the input field. The default is 1, but type any number including decimals.
- Select your source unit from the dropdown — milliohms (mΩ), ohms (Ω), kilohms (kΩ), megohms (MΩ), or gigohms (GΩ).
- Read every conversion at once. All 5 result boxes update live as you type or change units.
- Compare values directly. If you're checking whether a MOSFET's 50 m - RDS(on) matters next to your 0.2 Ω wire resistance, you'll see both in the same unit instantly.
- Adjust and iterate. Change the input value or unit anytime — the converter recalculates immediately.
Electrical Resistance Unit Formula
Resistance unit conversion follows a single, simple rule — convert the source value to ohms, then divide by the target unit's factor.
Rtarget = Rsource × (Factorsource ÷ Factortarget)
Rohms = Rsource × Factorsource
First convert to base ohms, then divide by the target factor.
| Symbol | Variable | Factor (relative to Ω) |
|---|---|---|
| mΩ | Milliohm | 0.001 |
| Ω | Ohm (base unit) | 1 |
| kΩ | Kilohm | 1,000 |
| MΩ | Megohm | 1,000,000 |
| GΩ | Gigohm | 1,000,000,000 |
Simple Example
Problem: Convert 1 kΩ to all other resistance units.
Step 1 — Convert to base ohms:
1 kΩ × 1,000 = 1,000 Ω
Step 2 — Divide by each target factor:
1,000 ÷ 0.001 = 1,000,000 mΩ
1,000 ÷ 1 = 1,000 Ω
1,000 ÷ 1,000 = 1 kΩ (identity)
1,000 ÷ 1,000,000 = 0.001 MΩ
1,000 ÷ 1,000,000,000 = 0.000001 GΩ
Practical meaning: 1 kΩ is a common pull-up or pull-down resistor value in signal circuits — well above any wire or MOSFET resistance, and well below any insulation resistance.
Engineering Applications
MOSFET RDS(on) and Conduction Losses in PWM Controllers
If you're building or selecting a PWM controller for a linear actuator, the MOSFET's on-resistance — RDS(on) — is one of the most important specs on the datasheet. It's always specified in milliohms. A typical value might be 50 mΩ, which is 0.050 Ω. That sounds tiny until you do the math. At 5 A of continuous actuator current, the power dissipated in that MOSFET is P = I² × R = 25 × 0.050 = 1.25 W. That's real heat in a small package.
If you're running an H-bridge with 2 MOSFETs conducting at any given time, you double that — 2.5 W just from conduction losses. This is why we always recommend checking the RDS(on) value and converting it to ohms so you can calculate power loss in familiar terms. A 10 mΩ MOSFET at the same 5 A only dissipates 0.25 W per device. The difference is night and day for thermal management.
Wire Resistance and Voltage Drop at High Actuator Currents
Wire resistance gets overlooked constantly. People run 10 feet of 18 AWG wire to a remote actuator and wonder why it's sluggish or stalls under load. The resistance of 18 AWG copper wire is about 6.385 Ω per 1,000 feet — or roughly 0.064 Ω for 10 feet. That's just one conductor. Round-trip (power and ground), you're looking at 0.128 Ω.
At 10 A, that's a voltage drop of V = I × R = 10 × 0.128 = 1.28 V. On a 12 V system, you just lost over 10% of your supply voltage before it even reaches the actuator. That 1.28 V drop also means 12.8 W of wasted power heating your wiring. The fix? Use thicker wire — 14 AWG or 12 AWG — or shorten the run. Either way, you need to know the resistance in ohms to calculate the drop, and this converter makes it trivial to go from the per-thousand-feet spec to actual ohms for your specific run length.
Insulation Resistance — Spotting Moisture Ingress and Damage
Insulation resistance testing tells you whether the dielectric barrier between conductors (or between a conductor and chassis) is intact. Healthy insulation should measure in the megohm to gigohm range — typically above 100 MΩ for motor windings and above 1 GΩ for high-quality cable insulation. When you see values drop below 1 MΩ, something is wrong. Moisture ingress, cracked insulation, contamination — any of these degrade the dielectric and create leakage paths.
In outdoor actuator installations, this is especially critical. An actuator rated IP65 should maintain high insulation resistance for years. But if the seals are compromised and you measure 500 kΩ between the motor winding and the housing, that's 0.5 MΩ — well below the acceptable threshold. You need to convert that kΩ reading to MΩ to compare it against the spec. This converter lets you do that instantly, and the logarithmic scale diagram above gives you the intuition for where that value falls — firmly in the "investigate immediately" zone.
Advanced Example
Scenario: You're designing a PWM driver for a 12 V, 8 A linear actuator. The H-bridge uses 4 MOSFETs, each with RDS(on) = 28 mΩ. The actuator sits 15 feet from the controller, connected with 16 AWG wire (4.016 Ω per 1,000 ft). You also have a 10 mΩ current sense resistor in the low-side return path. What's the total series resistance, and how much voltage reaches the actuator at full load?
Step 1 — Convert MOSFET RDS(on) to ohms:
28 mΩ × 0.001 = 0.028 Ω per MOSFET
In an H-bridge, 2 MOSFETs conduct at a time: 2 × 0.028 = 0.056 Ω
Step 2 — Calculate wire resistance (round-trip):
15 ft × 2 (out and back) = 30 ft total
30 ÷ 1,000 × 4.016 = 0.120 Ω
Step 3 — Convert sense resistor to ohms:
10 mΩ × 0.001 = 0.010 Ω
Step 4 — Total series resistance:
0.056 + 0.120 + 0.010 = 0.186 Ω = 186 mΩ
Step 5 — Voltage drop at 8 A:
Vdrop = 8 × 0.186 = 1.488 V
Step 6 — Voltage at actuator:
12° 1.488 = 10.51 V
Step 7 — Total power wasted:
P = I² × R = 64 × 0.186 = 11.9 W
Design interpretation: The actuator receives only 10.51 V — a 12.4% loss. Nearly 12 W gets wasted as heat. The wire is the biggest offender at 0.120 Ω (65% of total resistance). Upgrading to 12 AWG wire (1.588 Ω per 1,000 ft) would cut wire resistance to 0.048 Ω, dropping total loss to 8.5 W and delivering 11.09 V to the actuator. That's a meaningful improvement for a simple wire swap.
Frequently Asked Questions
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About the Author
Robbie Dickson — Chief Engineer & Founder, FIRGELLI Automations
Robbie Dickson brings over two decades of engineering expertise to FIRGELLI Automations. With a distinguished career at Rolls-Royce, BMW, and Ford, he has deep expertise in mechanical systems, actuator technology, and precision engineering.
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