Heat Transfer Conduction Calculator + Formula, Examples & Applications
Your linear actuator motor is running hot, and you need to figure out how much heat actually flows through that aluminium mounting plate into the chassis. That's a conduction problem — and it's one of the most common thermal questions we see in motion system design. This calculator uses Fourier's Law to give you the heat flow rate in watts and BTU/hr, plus the thermal resistance of your material. Just pick a material, enter thickness, area, and temperature difference, and you'll get answers you can design around. We've included worked examples, application notes, and a full formula breakdown below.
What Is Heat Transfer by Conduction?
Conduction is heat moving through a solid material from a hot side to a cold side. The rate depends on the material's thermal conductivity, its thickness, the contact area, and the temperature difference across it.
Simple Explanation
Think of a metal plate as a pipe for heat — wider pipe and shorter length means more flow. A material with high thermal conductivity (like aluminium) is a fat pipe. A material with low conductivity (like ABS plastic) is a pinhole. The bigger the temperature difference between the 2 sides, the harder heat pushes through — just like voltage drives current through a resistor.
Heat Transfer (Conduction) Calculator
Heat Transfer Conduction Interactive Visualizer
Watch heat flow through materials in real-time using Fourier's Law. Adjust material properties, thickness, area, and temperature difference to see how heat transfer rates and thermal resistance change instantly.
HEAT FLOW
3,331 W
BTU/HR
11,366
RESISTANCE
0.012 °C/W
FIRGELLI Automations — Interactive Engineering Calculators
🎥 Video — Heat Transfer (Conduction) Calculator
How to Use This Calculator
Getting a result takes about 15 seconds. Here's the process:
- Select your material from the dropdown. The calculator auto-fills the correct thermal conductivity value. If your material isn't listed, choose "Custom" and enter k manually.
- Enter the material thickness in inches. This is the distance heat has to travel through the solid — for a mounting plate, it's the plate thickness.
- Enter the surface area in square inches. This is the contact area through which heat flows, not the total surface area of the part.
- Enter the temperature difference in °F between the hot side and the cold side. If you know your motor housing runs at 160°F and the chassis sits at 120°F, ΔT is 40°F.
- Hit Calculate. You'll get heat flow in watts and BTU/hr, plus the thermal resistance of that material path. Lower resistance means a better heat path.
Heat Transfer (Conduction) Formula
Everything in this calculator comes from Fourier's Law of heat conduction — the foundational equation for steady-state heat flow through a solid:
Where Q is the heat flow rate in watts. To convert to BTU/hr:
Thermal resistance — the key design number that tells you how hard it is for heat to get through:
And the unit conversions the calculator handles for you:
area (m²) = area (in²) × 0.000645
ΔT (°C) = ΔT (°F) — same numerical value for a temperature difference
| Symbol | Variable | Unit |
|---|---|---|
| Q | Heat flow rate | W (watts) or BTU/hr |
| k | Thermal conductivity | W/m·K |
| A | Cross-sectional area | m² (input in inches²) |
| ΔT | Temperature difference (T₁ − T₂) | °C (input in °F) |
| d | Material thickness | m (input in inches) |
| R | Thermal resistance | °C/W |
Simple Example
Scenario: You're mounting a FIRGELLI linear actuator to an aluminium bracket. The motor housing runs 40°F hotter than the chassis. The mounting plate is 0.25 inches thick with a 4 in² contact area. How much heat flows through the plate?
Given values:
- Material: Aluminium — k = 205 W/m·K
- Thickness: 0.25 inches
- Area: 4 in²
- ΔT: 40°F
Step 1 — Convert units:
thickness_m = 0.25 × 0.0254 = 0.00635 m
area_m2 = 4 × 0.000645 = 0.00258 m²
ΔT_C = 40 (same numerical value for a difference)
Step 2 — Calculate heat flow:
Q = 205 × 0.00258 × 40 / 0.00635
Q = 21.156 / 0.00635 = 3,331.18 W
Step 3 — Convert to BTU/hr:
Q = 3,331.18 × 3.412 = 11,365.79 BTU/hr
Step 4 — Thermal resistance:
R = 0.00635 / (205 × 0.00258) = 0.00635 / 0.5289 = 0.0120 °C/W
What this means: That aluminium plate is an excellent heat conductor. With a thermal resistance of just 0.012 °C/W, it barely impedes heat flow at all. Aluminium is doing exactly what you want in a mounting bracket — moving heat away from the motor into the larger chassis where it can dissipate.
Engineering Applications
Actuator Motor Heat Management
Conduction is how heat moves through solid material — the mounting plate between a hot actuator motor and a cold chassis is a textbook conduction problem. Every linear actuator generates waste heat in its motor, and that heat needs to go somewhere. If the motor sits on a thick steel plate with minimal contact area, thermal resistance climbs and the motor runs hotter. We see this cause premature failures in high-duty-cycle applications all the time. The fix is usually straightforward: increase the contact area, choose a more conductive material, or reduce the material thickness between the heat source and the heat sink.
Why Aluminium Wins for Heat Spreading
Aluminium is the best practical choice for heat spreading in motion system designs. At 205 W/m·K, it conducts heat roughly 4 times better than mild steel and about 12 times better than stainless steel. Yes, copper at 385 W/m·K beats it handily — but copper costs significantly more, weighs more, and is harder to machine. For actuator mounting brackets, electronics enclosures, and heat sink plates, aluminium gives you the best balance of thermal performance, weight, machinability, and cost. We use it extensively in our own product designs for exactly these reasons.
The Thickness Relationship
Thinner material conducts more heat — halve the thickness and you double the heat flow rate. This is one of those relationships that catches people off guard. If you're designing a mounting plate and you want maximum heat transfer, make it as thin as structural requirements allow. Of course, you can't sacrifice mechanical strength — but the point is that a 0.125-inch aluminium plate transfers twice as much heat as a 0.25-inch plate, all else being equal. That's a free thermal upgrade if the thinner plate still meets your load requirements.
Plastic Enclosures Are Near-Insulators
Here's one that surprises a lot of people. ABS plastic has a thermal conductivity of just 0.17 W/m·K — that's roughly 1,200 times worse than aluminium. If your control electronics sit inside a plastic enclosure, you're relying almost entirely on convection (air movement) and radiation to get heat out. Conduction through the enclosure walls is doing almost nothing for you. This matters for actuator controllers, relay boxes, and any electronics in sealed enclosures. If heat is a concern, consider an aluminium enclosure or at least aluminium mounting plates that create a conductive path to the outside.
Thermal Resistance — The Design Number That Matters
Thermal resistance R is the single most useful number for comparing heat paths. Lower R means a better heat path — think of it like electrical resistance, but for heat instead of current. A good conductive path might have R of 0.01 °C/W, meaning for every watt of heat flowing through, the temperature only drops 0.01°C across the material. A bad path — like an air gap or plastic wall — could have R of 100 °C/W or more. When you're designing a thermal management system, you calculate R for each element in the heat path and add them up, just like resistors in series. The element with the highest R is your bottleneck.
Advanced Example
Scenario: You're building an outdoor automation system with a control board mounted inside an ABS plastic enclosure. The board generates 15W of heat. The enclosure wall is 0.125 inches thick, and the board-to-wall contact area is 6 in². Ambient temperature outside is 95°F and you want to know if conduction alone can keep the board under 140°F — a 45°F allowable rise.
Given values:
- Material: ABS Plastic — k = 0.17 W/m·K
- Thickness: 0.125 inches
- Area: 6 in²
- ΔT: 45°F
Step 1 — Convert units:
thickness_m = 0.125 × 0.0254 = 0.003175 m
area_m2 = 6 × 0.000645 = 0.00387 m²
ΔT_C = 45
Step 2 — Calculate heat flow capacity:
Q = 0.17 × 0.00387 × 45 / 0.003175
Q = 0.02960 / 0.003175 = 9.33 W
Step 3 — Convert to BTU/hr:
Q = 9.33 × 3.412 = 31.83 BTU/hr
Step 4 — Thermal resistance:
R = 0.003175 / (0.17 × 0.00387) = 0.003175 / 0.0006579 = 4.8257 °C/W
Design interpretation: At a 45°F temperature difference, conduction through the ABS wall can only move 9.33W — but the board generates 15W. That means conduction alone falls short by about 5.7W. The board will exceed 140°F unless you add ventilation (convection), use a metal heat sink plate that conducts heat to the wall, or switch to an aluminium enclosure. The thermal resistance of 4.83 °C/W tells the same story — for every watt pushed through, you need almost 5°C of temperature difference. Compare that to the aluminium plate in our simple example at 0.012 °C/W. That's a 400× difference in thermal resistance. This is exactly why we recommend aluminium enclosures for high-duty-cycle actuator controllers.
Frequently Asked Questions
Thermal management doesn't have to be complicated. Start with the conduction path — it's the one you have the most control over in your mechanical design. Pick the right material, size the contact area, and keep the path short. If the numbers from this calculator show your mounting setup can handle the heat, you're in good shape. If they don't... now you know exactly what to change.
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About the Author
Robbie Dickson — Chief Engineer & Founder, FIRGELLI Automations
Robbie Dickson brings over two decades of engineering expertise to FIRGELLI Automations. With a distinguished career at Rolls-Royce, BMW, and Ford, he has deep expertise in mechanical systems, actuator technology, and precision engineering.
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