Steam Trap (form 2) Mechanism, Diagram, Parts, Uses, and Sizing Formula Explained

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This partial calculator derives an equivalent circular area from an entered reference pressure and force, then applies a selected differential pressure to that same area. It does not predict float lift, valve opening, trap capacity or safe operation.

Steam Trap Form 2 - Selected Pressure-Force Reference Ledger

Explore an entered pressure-force reference pair and ideal force scaling on its equivalent circular area.

0°

Selected Ideal Pressure Force
--
Reference-Equivalent Area
--
Equivalent Circular Diameter
--
Selected-to-Reference Force Ratio
--

Equation Used

A=F_ref/(Delta P_ref 100000); d=sqrt(4A/pi); F_selected=A Delta P 100000.
Selected ideal pressure-force arithmetic only; no float lift, valve, flow, capacity or safety prediction.
  • Selected differential, reference differential and reference force are entered values.
  • One bar equals 100000 pascals and one pascal equals one newton per square metre.
  • The equivalent area is circular only for diameter display.
  • Selected pressure force acts ideally and uniformly on the reference-equivalent area.
  • Mechanism forces, flow, capacity and safety are excluded.

The secondary figure is an abstract pressure-force ledger, not a steam-trap design.

Same mechanism and inputs as the interactive calculator.

Selected pressure-force reference ledger

Using pressure force F=pA, the entered reference pair defines area A=F_ref/(Delta P_ref times 100000). An equivalent circular diameter follows from d=sqrt(4A/pi). Selected ideal pressure force is the same area times the entered differential pressure.

What the calculator determines

Use it to inspect ideal pressure-force scaling for one selected equivalent area. It cannot establish actual trap forces or geometry.

Selected relationships

A=F_ref/(Delta P_ref 100000); d=sqrt(4A/pi); F_selected=A Delta P 100000; force ratio=100 Delta P/Delta P_ref.

Selected-input example

At 14 bar reference pressure and 45 N reference force, the equivalent area is about 32.143 mm2 and diameter about 6.397 mm. At 14 bar selected differential, ideal pressure force remains 45 N.

Not a mechanism or sizing model

Lever ratio, buoyancy, float weight, friction, valve profile, flow, manufacturer capacity, phase behavior, piping and safety are excluded.

Questions

Is selected pressure force float lift demand?

No. It is ideal pressure force on the reference-equivalent area only.

Why does equivalent area not change with selected differential?

It is defined entirely by the entered reference pressure-force pair; selected pressure is then applied to that fixed area.

Can this size a trap?

No. Actual selection requires manufacturer data and complete mechanism and system conditions.

Authoritative references

References & Further Reading

  • Wikipedia contributors. Steam trap. Wikipedia

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