Heat Transfer (Conduction) Calculator

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Heat Transfer Conduction Calculator + Formula, Examples & Applications

If your actuator motor is running hot and you need to estimate how much heat is being conducted through an aluminium plate into a chassis, this is a straightforward conduction problem. Problems like this come up often in motion system work. This calculator is based on Fourier's Law, giving you heat flow rate in watts and BTU/hr, along with the thermal resistance of whatever material you use. Pick a material, enter its thickness, area, and the temperature difference across it. You’ll get numbers you can work with for practical design. There are examples and more details further down.

What Is Heat Transfer by Conduction?

Conduction is the transfer of heat through a solid, from the hotter side to the colder side. The speed of this process depends on the material’s conductivity, how thick the material is, the area of the contact, and the temperature difference you’ve got across it.

Simple Explanation

You can think of a metal plate as a physical path for heat—if the path is wide and short, more heat goes through, just like more water through a wide, short pipe. Aluminium behaves like a wide-open pipe for heat, while a plastic like ABS is more like a pinhole. The bigger the temperature difference, the harder heat “pushes” to move through, similar to how voltage pushes current through a resistor.

HOT SIDE T₁ Material (conductivity k) d (thickness) Area A COLD SIDE T₂ Q → ΔT = T₁ − T₂ Fourier's Law Q = k·A·ΔT / d (watts) Resistance R = d / (k·A)

Heat Transfer (Conduction) Calculator

Converted to metres internally.
Contact area through which heat flows. Converted to m² internally.
ΔT is the same numerical value in °F and °C for a temperature difference.
Engineering calculation notice

This calculator is intended for education, concept evaluation, and preliminary design. Results are based on the equations and assumptions described on this page, but cannot account for every real-world load case, tolerance, material property, environmental condition, installation detail, safety factor, code, or regulatory requirement. Verify all inputs, assumptions, units, and results independently before selecting components or using the result in a real application. Safety-critical, structural, medical, lifting, transportation, or regulated applications must be reviewed by a qualified engineer.

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Heat Transfer Conduction Interactive Visualizer

You can see how changes in material, thickness, area, and temperature difference affect heat transfer rate and thermal resistance. Adjust parameters and the results change instantly based on Fourier's Law.

Material
Thickness 0.25 in
Surface Area 4.0 in²
Temperature Diff ΔT 40 °F

HEAT FLOW

3,331 W

BTU/HR

11,366

RESISTANCE

0.012 °C/W

FIRGELLI Automations — Interactive Engineering Calculators

🎥 Video — Heat Transfer (Conduction) Calculator

Heat Transfer (Conduction) Calculator

How to Use This Calculator

This isn't complicated. Here’s what you do:

  1. Select your material from the dropdown. The calculator fills in the thermal conductivity for standard choices. If your material isn’t there, use “Custom” and enter the value directly.
  2. Enter the material thickness in inches. For a bracket or a plate, use the actual physical thickness the heat needs to cross.
  3. Enter the surface area in square inches. This should be the area touching both sides that is actually conducting heat—not the total part surface.
  4. Enter the temperature difference in °F. Subtract the cold side temperature from the hot side to get ΔT. For example, if one side is 160°F, the other is 120°F, ΔT is 40°F.
  5. Hit Calculate. You'll see the heat flow (watts and BTU/hr) and the thermal resistance. If resistance is low, the material is a good heat path. If it’s high, it’s not.

Heat Transfer (Conduction) Formula

This is all based on Fourier’s Law—the workhorse for steady-state conduction through solids:

Q = k × A × ΔT / d

Where Q is how much heat flows, in watts. For BTU/hr, just multiply by 3.412:

Q (BTU/hr) = Q (W) × 3.412

Thermal resistance tells you how much the material slows down heat flow:

R = d / (k × A)

This calculator handles the unit conversions, but these are the conversions used:

thickness (m) = thickness (inches) × 0.0254
area (m²) = area (in²) × 0.000645
ΔT (°C) = ΔT (°F)  — for temperature difference only
Symbol Variable Unit
Q Heat flow rate W (watts) or BTU/hr
k Thermal conductivity W/m·K
A Cross-sectional area m² (input in inches²)
ΔT Temperature difference (T₁ − T₂) °C (input in °F)
d Material thickness m (input in inches)
R Thermal resistance °C/W

Simple Example

Scenario: You’re mounting a linear actuator to an aluminium bracket. The motor runs 40°F hotter than the chassis. Plate is 0.25” thick, contact area is 4 in². What’s the heat flow?

Given values:

  • Material: Aluminium — k = 205 W/m·K
  • Thickness: 0.25 inches
  • Area: 4 in²
  • ΔT: 40°F

Step 1 — Convert units:

thickness_m = 0.25 × 0.0254 = 0.00635 m

area_m2 = 4 × 0.000645 = 0.00258 m²

ΔT_C = 40 (same as ΔT_F)

Step 2 — Calculate heat flow:

Q = 205 × 0.00258 × 40 / 0.00635 = 3,331.18 W

Step 3 — Convert to BTU/hr:

Q = 3,331.18 × 3.412 = 11,365.79 BTU/hr

Step 4 — Thermal resistance:

R = 0.00635 / (205 × 0.00258) = 0.0120 °C/W

What this means: That bracket offers very little resistance to heat, so most waste heat from the motor will flow into the chassis—just what you want for reliable cooling.

Engineering Applications

Actuator Motor Heat Management

Whenever you see a hot actuator mounted to a colder chassis, the heat mostly moves by conduction through the mounting plate or bracket. The step that often causes trouble is using a thick steel plate with a small contact area. This ramps up total resistance, so the motor runs hotter. I've seen a lot of early failures traced back to small or poorly-conducting mounting details. The practical fix is to use the largest contact area you can, go for better-conducting materials, or keep that plate as thin as structural strength allows.

Why Aluminium Wins for Heat Spreading

Aluminium is popular in mechanical work for good reason. At 205 W/m·K, it moves heat much faster than mild steel (about 4×), and absolutely dwarfs stainless. Copper is technically better at 385 W/m·K, but it’s heavy, expensive, and awkward to machine for most brackets or enclosures. Aluminium holds a good balance—strong, lightweight, cheaper, and adequate for almost any actuator-mounting job that needs good heat flow.

The Thickness Relationship

Thick material slows heat, thin material helps it move. If you cut plate thickness in half and leave everything else the same, you double your heat transfer rate. If your part can be thinner and still support the load, this is the easiest way to upgrade your thermal path for free.

Plastic Enclosures Are Near-Insulators

Plastics like ABS barely let any heat through—thermal conductivity is less than 1/1,000th of typical metals. If you put electronics in a plastic box, almost no heat leaves by conduction. You're relying mostly on airflow (convection) or radiation. If overheating is on your radar, switch to an aluminium box or at least use an internal plate to get heat to the outer wall.

Thermal Resistance — The Design Number That Matters

Thermal resistance is your main metric for comparing heat paths. Think of it like electrical resistance, only for heat. Lower R means less temperature rise for the same heat flow—better cooling. Every layer in your heat path (metal, interface, etc.) adds up like resistors in series. The highest R usually chokes the system. If you do the math and see a high R somewhere, that's the weak link to redesign.

Advanced Example

Scenario: You have a control board making 15W heat in an ABS enclosure. Wall is 0.125” thick, circuit board touches 6 in² of enclosure wall, outside is 95°F, and you want to keep the board under 140°F (so max 45°F rise allowed). Can conduction keep it cool?

Given values:

  • Material: ABS Plastic — k = 0.17 W/m·K
  • Thickness: 0.125 inches
  • Area: 6 in²
  • ΔT: 45°F

Step 1 — Convert units:

thickness_m = 0.125 × 0.0254 = 0.003175 m

area_m2 = 6 × 0.000645 = 0.00387 m²

ΔT_C = 45

Step 2 — Calculate heat flow capacity:

Q = 0.17 × 0.00387 × 45 / 0.003175 = 9.33 W

Step 3 — Convert to BTU/hr:

Q = 9.33 × 3.412 = 31.83 BTU/hr

Step 4 — Thermal resistance:

R = 0.003175 / (0.17 × 0.00387) = 4.8257 °C/W

Design interpretation: With just conduction, you can only move about 9.3W—not enough for the 15W heat the board puts out. If you need to stay under 140°F, conduction won’t cut it. You'll need to add ventilation, boost surface area with a metal plate, or change the enclosure material. That resistance value compared to aluminium shows just how poor plastics are for moving heat out.

Frequently Asked Questions

Why does the calculator say ΔT is the same in °F and °C? +

A difference of 1°F is numerically identical to a difference of 1°C when you’re just working with temperature intervals, not absolute temps. For conduction calculations, the scale step size is what matters, and both scales use the same step size when looking at differences (not actual readings). So a 40°F difference is handled the same as 40°C—the math holds up.

Does this calculator account for convection and radiation? +

No—it’s strictly for conduction through a solid. If you want to account for heat lost by air movement or thermal radiation, you’ll need other calculations. For actuator mounting, conduction is the dominant heat path you can control mechanically. The other modes matter, but they’re separate.

What is thermal contact resistance, and should I worry about it? +

That’s the extra resistance you get at the junction where two surfaces touch. Even machined plates make contact only at microscopic points, so there’s always a bit of extra resistance beyond what you’d calculate for the bulk materials. This tool ignores contact resistance, but if you want accuracy: improve surface finish, bolt parts together tightly, or add thermal paste or pads in between. For actuator brackets, a thin layer of paste and tight hardware is often all you need.

Can I use this for multi-layer materials? +

No, this calculator is for one material layer at a time. For a stack-up (like aluminium plate plus a steel frame), work out R for each layer, then add them. The sum is your total system thermal resistance: Q = ΔT / R_total. It’s just like resistors in series in a circuit.

Why does the air gap option exist if air conducts so poorly? +

Because air is such a bad conductor, any air gap in your design shows up as a massive resistance. You can use the calculator to see how much an unintentional gap will rob you of cooling, which is why it’s included—to highlight why metal-to-metal or metal-to-thermal-pad contact matters.

Does thermal conductivity change with temperature? +

Thermal conductivity does shift with temperature, but in typical actuator and automation work (–20°F to 300°F), that change is minimal. The values in the calculator (room temperature) are close enough for working estimates. For really high or low temperatures, get data from material datasheets specific to your operating range.

In practice, thermal management comes down to managing the main conduction path. Choose the right material, give the heat somewhere to go, make the path as short and wide as practical, and let the math confirm you’re on track. If your calculations say it won't handle your motor heat, adjust thickness, area, or material. That way you catch problems before they cause a hardware failure.

About the Author

Robbie Dickson — Chief Engineer & Founder, FIRGELLI Automations

Robbie Dickson brings over two decades of engineering expertise to FIRGELLI Automations. With a distinguished career at Rolls-Royce, BMW, and Ford, he has deep expertise in mechanical systems, actuator technology, and precision engineering.

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