If you don’t have good mass transfer data, it’s easy to size evaporation systems incorrectly. That usually means the equipment comes up short, drying targets aren’t hit, and energy is wasted. The Evaporation Rate Interactive Calculator is a tool to give you rough answers for evaporation rate, mass transfer coefficient, vapor pressure difference, surface area, or time to evaporate a set liquid volume. You’ll need to enter liquid properties, temperature, surface area, and vapor pressures. Getting even a ballpark value is useful across several fields—chemical plant design, industrial drying, HVAC, and projects like evaporation ponds. The equations, a realistic worked example, main theory, and FAQ are included below so you can see how things are put together and what assumptions are baked in.
What is evaporation rate?
Evaporation rate is just how much liquid (by mass) turns into vapor per second—usually in kg/s. It measures the speed at which liquid mass leaves the surface for the air, based on whatever set of conditions you’ve got.
Simple Explanation
Think about a puddle after a rainstorm. When the wind picks up, the water doesn’t last long. That’s because the moving air gets rid of the humid layer at the surface, letting more water escape—even on a mild day. A bigger puddle, drier air, faster wind, and warmer temps all speed things up. This calculator helps you put numbers to those variables, so you aren’t left guessing.
📐 Browse all 1000+ Interactive Calculators
Quick Navigation
System Diagram
Evaporation Rate Calculator
How to Use This Calculator
This calculator is intended for education, concept evaluation, and preliminary design. Results are based on the equations and assumptions described on this page, but cannot account for every real-world load case, tolerance, material property, environmental condition, installation detail, safety factor, code, or regulatory requirement. Verify all inputs, assumptions, units, and results independently before selecting components or using the result in a real application. Safety-critical, structural, medical, lifting, transportation, or regulated applications must be reviewed by a qualified engineer.
- Pick the mode—decide if you’re solving for evaporation rate, mass transfer coefficient, vapor pressure difference, surface area, or evaporation time.
- Enter the variables shown for that mode. You’ll need values like the mass transfer coefficient (k), surface area (A), vapor pressures (Psat, P∞), molecular weight (M), and temperature (T).
- Check that your units match what’s listed—pressure in Pa, temperature in K, area in m², molecular weight in kg/kmol.
- Press Calculate to get your result.
Evaporation Rate Interactive Visualizer
Watch how mass transfer coefficient, surface area, and vapor pressure difference control evaporation rate in real-time. Adjust parameters to see immediate effects on molecular transport and drying performance.
EVAPORATION RATE
34.9 µg/s
MASS FLUX
17.5 µg/m²s
RATE EFFICIENCY
82%
FIRGELLI Automations — Interactive Engineering Calculators
Governing Equations
The evaporation rate comes from the equation here, which uses mass transfer coefficient, surface area, molecular weight, temperature, and vapor pressure difference. Values below are in standard SI units.
Mass Transfer Rate Equation
E = k · A · (M / (R · T)) · (Psat - P∞)
E = evaporation rate (kg/s)
k = mass transfer coefficient (m/s)
A = evaporating surface area (m²)
M = molecular weight of evaporating species (kg/kmol)
R = universal gas constant = 8314.46 J/(kmol·K)
T = absolute temperature (K)
Psat = saturation vapor pressure at liquid surface (Pa)
P∞ = partial vapor pressure in ambient air (Pa)
Mass Flux Equation
G = E / A = k · (M / (R · T)) · ΔP
G = mass flux per unit area (kg/(m²·s))
ΔP = vapor pressure difference = Psat - P∞ (Pa)
Evaporation Time Equation
t = (V · ρ) / E
t = time to completely evaporate (s)
V = liquid volume (m³)
ρ = liquid density (kg/m³)
Antoine Equation (Vapor Pressure)
log10(Psat) = A - (B / (C + T))
A, B, C = substance-specific Antoine coefficients
For water: A = 8.07131, B = 1730.63, C = 233.426 (with T in °C, P in mmHg)
Simple Example
Take a case with water evaporating from a 2 m² open tank at 20°C (293.15 K), mass transfer coefficient k = 0.0025 m/s, Psat = 2338 Pa, P∞ = 1000 Pa, and molecular weight M = 18.015 kg/kmol:
- ΔP = 2338 − 1000 = 1338 Pa
- E = 0.0025 × 2 × (18.015 / (8314.46 × 293.15)) × 1338
- E ≈ 3.49 × 10⁻⁵ kg/s
Theory & Practical Applications
Fundamental Mass Transfer Physics
Evaporation is an interface process—molecules leave the surface and enter the gas above. What drives evaporation is a difference in vapor pressure between the liquid surface (which is saturated) and the bulk gas phase (which is usually drier). It’s not like boiling; boiling happens when vapor bubbles form inside the liquid, but evaporation is always at the surface and can happen at any temperature (though it gets much faster near boiling point).
The mass transfer coefficient k acts as a catch-all for the mixing and diffusion happening right above the liquid. In still air, k for water is usually between 0.0005 and 0.003 m/s. Add a fan, and k shoots up—a stiff breeze (2-5 m/s) can push k to 0.01-0.025 m/s or more. It’s not a linear relationship; k follows empirical laws linked to flow velocity and fluid properties, usually expressed in terms of Sherwood, Reynolds, and Schmidt numbers. For a quick estimate, focus on air speed and geometry; just know that k can change a lot, and small mistakes here will throw off calculations.
Evaporation needs heat—specifically, the latent heat of vaporization. For every kg of water evaporated at 20°C, you need about 2454 kJ of energy. If you don’t supply this heat, the liquid cools itself down, which lowers its vapor pressure and causes evaporation to slow. In closed or poorly ventilated situations, expect the surface temperature to drop a few degrees (5-8°C isn’t uncommon) before things find a new equilibrium. Don’t ignore this effect when running heat-and-mass balances—it shows up clearly when sizing equipment or estimating drying time.
Process engineers that overlook evaporative cooling often miss the mark on required area or underestimate time to dry.
Industrial Evaporation Applications
Tablet coating in pharma is a good case. Drying time must match production pace. For example, coating 500 kg/hour of tablets with a 15% ethanol-based layer means 75 kg/hour of solution (60% ethanol, so 45 kg/hour ethanol). Chamber runs at 35°C, forced air at 3.2 m/s, giving k ≈ 0.018 m/s for ethanol, around 28 m² of surface area (accounting for movement), and ethanol vapor pressure at 35°C is 13,680 Pa. If you hold chamber ethanol vapor at 2500 Pa, that supports an evaporation rate of about 0.0126 kg/s (45.4 kg/hour)—matching your coating input if everything’s steadied out.
In the chemical industry, multi-effect evaporators save steam by using vapor from one stage to heat the next. Example: concentrating sodium hydroxide from 10% to 50% (w/w), 10,000 kg/hour feed. The first effect operates at 115°C (water Psat = 169,100 Pa), evaporates about 6400 kg/hour, the next at 95°C, the last at 75°C. Each stage’s evaporation rate depends on how much area you have and how much of a pressure bump you can maintain between stages (that controls vapor flow).
Evaporation ponds for wastewater or brine disposal are another case. Take a lithium extraction site with 12 km² of ponds, average conditions of 22°C, 8% relative humidity, wind at 4.1 m/s. For brine, k ≈ 0.0085 m/s (lower than pure water because salt slows things down), Psat = 2640 Pa (a bit below pure water), P∞ = 211 Pa. The resulting rate is around 98,500 kg/s—about 8.5 million m³ per year—concentrating the lithium over more than a year and a half. As the brine gets thicker, you’ll see required residence time shoot up.
Worked Example: Industrial Solvent Recovery System
Consider a manufacturing plant reclaiming methyl ethyl ketone (MEK) from polymer processes. The setup heats contaminated MEK, vaporizes it, and then condenses the purified solvent. Equipment must be sized to handle 180 kg/hour. Here’s the breakdown:
Given Parameters:
- Target evaporation rate: E = 180 kg/hour = 0.050 kg/s
- Operating temp: T = 45°C = 318.15 K
- MEK molar mass: M = 72.11 kg/kmol
- MEK vapor pressure at 45°C: Psat = 28,400 Pa
- Chamber vapor pressure: P∞ = 8500 Pa (about 30% of saturation)
- Mass transfer coefficient: k = 0.0062 m/s (from supplier correlation, forced air design)
- R = 8314.46 J/(kmol·K)
Step 1: Calculate pressure differential
ΔP = Psat - P∞ = 28,400 - 8500 = 19,900 Pa
Step 2: Solve for required surface area using mass transfer equation
E = k · A · (M / (R · T)) · ΔP
Fill in values: 0.050 = 0.0062 · A · (72.11 / (8314.46 · 318.15)) · 19,900
Simplify: 0.050 = 0.0062 · A · (72.11 / 2,645,282) · 19,900
0.050 = 0.0062 · A · 0.00002726 · 19,900
0.050 = 0.0062 · A · 0.5425
0.050 = A · 0.003364
A = 0.050 / 0.003364 = 14.86 m²
Step 3: Calculate mass flux to verify against design limits
G = E / A = 0.050 / 14.86 = 0.00336 kg/(m²·s) = 12.1 kg/(m²·hour)
Step 4: Verify operational feasibility
This mass flux is in the usual design range for organic solvent evaporators (8–25 kg/(m²·hour)). So the solution is within expected reality. For a falling-film design, you’d set up about 15.5 m² using 42 vertical tubes, each 2.5 m long with 47 mm outside diameter, which gets you that surface area with a little margin added.
Step 5: Calculate energy requirement
Latent heat for MEK at 45°C: hfg = 425 kJ/kg
Thermal input needed: Q = E · hfg = 0.050 kg/s · 425,000 J/kg = 21,250 W
Add about 15% for system heat losses and 8% for bringing stored MEK from 25°C to 45°C (specific heat 2.2 kJ/kg·K):
Qsensible = 0.050 · 2200 · 20 = 2200 W
Qtotal = (21,250 + 2200) · 1.15 = 26,968 W, call it 27 kW.
This work-through shows the steps from mass transfer basics to estimating the surface and heat you need. Getting k right is often the weak link—you may have to run pilot trials or lean on prior data for a close number. If you want more examples for other thermal and mass transfer jobs, check the main calculator library.
Factors Affecting Mass Transfer Coefficient
k isn’t a fixed value—fluid properties, flow regime, and geometry all affect it. For evaporation into air from flat horizontal surfaces using natural convection, you can use correlations based on Sherwood and Rayleigh numbers: Sh = 0.54·Ram1/4 (if 10⁴ < Ram < 10⁷) or Sh = 0.15·Ram1/3 (for higher Ram). Here, Ram takes into account both concentration and temperature effects on buoyancy.
If you’re using forced convection over a flat plate, the textbook formulas are Sh = 0.664·Re1/2·Sc1/3 (laminar), and Sh = 0.037·Re0.8·Sc1/3 (turbulent, Re > 5e5). The Schmidt number, Sc = ν/D (kinematic viscosity divided by diffusion coefficient), is about 0.6 for water vapor in air at 20°C, but is higher for solvents. These are starting points for calculating k—just know that real-life hardware, like packed beds or wind-affected ponds, almost always needs some “fudge factor” or test data to nail k down.
Vapor Pressure Temperature Dependence
Evaporation calculations are sensitive to vapor pressure, which itself is very sensitive to temperature. Antoine’s equation gives more accurate values than Clausius-Clapeyron, especially for organics. For example: water’s vapor pressure at 20°C is 2338 Pa, but at 40°C it’s 7384 Pa—a jump of over threefold for just 20°C of temperature change. So even minor temperature control errors (a couple degrees either way) can throw off rates by more than 10%.
In mixtures, dissolved salts or other solutes lower the solvent vapor pressure, according to Raoult’s law: Pi = xi·γi·Pi,sat, where xi is the liquid-phase mole fraction, γi is the activity coefficient, and Pi,sat is the pure vapor pressure. Seawater at 3.5% salt has about 2% lower vapor pressure than pure water, so evaporation rates are measurably slower for brine and desalination ponds as concentration builds up.
Frequently Asked Questions
Free Engineering Calculators
Explore our complete library of free engineering and physics calculators.
Browse All Calculators →🔗 Explore More Free Engineering Calculators
About the Author
Robbie Dickson — Chief Engineer & Founder, FIRGELLI Automations
Robbie Dickson brings over two decades of engineering expertise to FIRGELLI Automations. With a distinguished career at Rolls-Royce, BMW, and Ford, he has deep expertise in mechanical systems, actuator technology, and precision engineering.
📹 Video Walkthrough — How to Use This Calculator
📹 Video Walkthrough — How to Use This Calculator
Need to implement these calculations?
Explore the precision-engineered motion control solutions used by top engineers.
