Sun Angle Interactive Calculator

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If you don't get the sun's position right, your solar panels won't deliver full output, your building can get too hot, or greenhouse lighting gets off schedule. This calculator works out solar elevation, azimuth, day length, incident angle, hour angle, and solar declination based on your input for location, date, and time. It's the kind of math you need for real decisions in solar panel layouts, passive building design, or planning light cycles in agriculture. All the underlying equations, an actual worked example, some straightforward background, and an FAQ are included below.

What is sun angle?

Sun angle boils down to how high the sun sits above the horizon (elevation), and which direction along the compass it's coming from (azimuth), for a specific place and time. Both numbers change constantly through the day and across the seasons.

Simple Explanation

The sun follows an arc: higher in the sky during summer, lower in winter, always moving east to west during the day. Sun angle tells you exactly where the sun sits on that arc at your location, at your chosen date and time. This calculator does with math what you could do with a compass and some patience: it pinpoints the sun's position.

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Sun Angle Diagram

Sun Angle Interactive Calculator Technical Diagram

Sun Angle Interactive Calculator

How to Use This Calculator

Engineering calculation notice

This calculator is intended for education, concept evaluation, and preliminary design. Results are based on the equations and assumptions described on this page, but cannot account for every real-world load case, tolerance, material property, environmental condition, installation detail, safety factor, code, or regulatory requirement. Verify all inputs, assumptions, units, and results independently before selecting components or using the result in a real application. Safety-critical, structural, medical, lifting, transportation, or regulated applications must be reviewed by a qualified engineer.

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  1. Pick the calculation mode you need — Sun Position, Solar Noon, Day Length, Incident Angle, Hour Angle, or Declination.
  2. Enter latitude/longitude in decimal degrees (use negative for south/west), day of year (1–365), and local solar time (decimal hours) as the mode requires.
  3. For surface-specific calculations such as Incident Angle, enter the surface tilt and azimuth as well.
  4. Hit Calculate to see your output.

Simple Example

Mode: Sun Position. Location: 40°N latitude. Day of year: 172 (summer solstice). Solar time: 12:00 (noon).

Solar declination = +23.45°. Hour angle = 0°.
Solar elevation = 90° − |40° − 23.45°| = 73.45°. Azimuth = 180° (due south).
At noon at this latitude on the summer solstice, the sun is nearly overhead — this is its annual peak height.

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Sun Angle Interactive Calculator

Sun Angle Interactive Visualizer

You can see for yourself how elevation and azimuth change as the day and seasons progress. Tweak latitude, day, and time to watch how the sun's path shifts — useful for anyone concerned with panel orientation or building shadows.

Latitude (°N) 40°
Day of Year 172
Solar Time (hrs) 12.0h

ELEVATION

73.5°

AZIMUTH

180°

DECLINATION

23.5°

HOUR ANGLE

0.0°

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Solar Position Equations

Solar Declination Angle

Use the formula below to calculate solar declination angle.

δ = 23.45° × sin[(360°/365) × (n - 81)]

Where:

  • δ = solar declination angle (degrees)
  • n = day of year (1-365)
  • 23.45° = Earth's axial tilt
  • 81 = approximate day of vernal equinox

Solar Elevation Angle

Use the formula below to calculate solar elevation angle.

sin(α) = sin(φ) × sin(δ) + cos(φ) × cos(δ) × cos(H)

Where:

  • α = solar elevation (altitude) angle above horizon (degrees)
  • φ = observer's latitude (degrees, positive north)
  • δ = solar declination angle (degrees)
  • H = hour angle (degrees, 15° per hour from solar noon)

Solar Azimuth Angle

Use the formula below to calculate solar azimuth angle.

cos(Az) = [sin(δ) - sin(φ) × sin(α)] / [cos(φ) × cos(α)]

Where:

  • Az = solar azimuth angle from north (degrees)
  • α = solar elevation angle (degrees)
  • φ = observer's latitude (degrees)
  • δ = solar declination angle (degrees)
  • Note: If H > 0 (afternoon), then Az = 360° - Az

Hour Angle

Use the formula below to calculate hour angle.

H = 15° × (tsolar - 12)

Where:

  • H = hour angle (degrees)
  • tsolar = local solar time (hours, decimal)
  • 15° = Earth's rotation rate (degrees per hour)
  • Negative before solar noon, positive after solar noon

Equation of Time

Use the formula below to calculate the equation of time correction.

EoT = 9.87 × sin(2B) - 7.53 × cos(B) - 1.5 × sin(B)

B = (360°/365) × (n - 81)

Where:

  • EoT = equation of time correction (minutes)
  • B = fractional year angle (degrees)
  • n = day of year (1-365)
  • Accounts for Earth's elliptical orbit and axial tilt

Sunrise/Sunset Hour Angle

Use the formula below to calculate sunrise/sunset hour angle.

cos(Hs) = -tan(φ) × tan(δ)

Where:

  • Hs = sunrise/sunset hour angle (degrees)
  • φ = observer's latitude (degrees)
  • δ = solar declination angle (degrees)
  • Day length = 2 × Hs / 15° (hours)

Incident Angle on Tilted Surface

Use the formula below to calculate incident angle on a tilted surface.

cos(θ) = sin(α) × cos(β) + cos(α) × sin(β) × cos(Az - γ)

Where:

  • θ = incident angle between sun rays and surface normal (degrees)
  • α = solar elevation angle (degrees)
  • β = surface tilt angle from horizontal (degrees)
  • Az = solar azimuth angle (degrees)
  • γ = surface azimuth angle (degrees, typically 0° for south-facing)

Theory & Practical Applications

Solar Geometry Fundamentals

Figuring out the sun's path is largely a geometry problem — one that comes from combining Earth's daily spin, its yearly trip around the sun, and the fact that Earth's axis is tilted. That tilt — 23.45° — is why the sun's arc gets higher in the sky in summer and lower in winter, and why day lengths change so much by latitude and season. If Earth orbited in a perfect circle and wasn't tilted, the sun would move in a straightforward way. In reality, the sun's apparent speed varies about ±3.4% during the year due to our elliptical orbit. This leads to the Equation of Time, which means the sun’s highest point can be off by up to 16 minutes from “clock noon.”

Solar declination (δ) cycles from +23.45° at the June solstice to -23.45° at the December solstice. At the equinoxes, it’s right at zero. This value tells you the maximum possible sun height for your location. At solar noon, max sun elevation is 90° minus the difference between your latitude and declination: 90° - |φ - δ|. At 40.7°N on the summer solstice (δ = +23.45°), that’s 72.75°. On the winter solstice (δ = -23.45°), it drops to 26.15°. That ~47° swing is the main reason for seasonal differences in heating.

Hour Angle and Time Systems

The hour angle (H) tells you how far the sun is from your local meridian, counting 15° per hour. At solar noon, H = 0°, positive in the afternoon, negative in the morning. To turn standard time into solar time, you need to adjust for time zone, your longitude versus the standard meridian, and the Equation of Time. Each degree of longitude is 4 minutes, so if you’re 1° east of the standard meridian, your solar noon hits 4 minutes before “clock noon.” That’s why solar calculations don’t quite match the time on your watch or phone unless you correct for these offsets.

The Equation of Time comes from two main factors. Earth’s not-quite-circular orbit speeds us up or slows us down on different calendar dates, and the tilt of the axis changes the sun’s apparent motion in a way that goes in and out of sync with the orbit. That’s why the difference between “solar noon” and “clock noon” isn’t the same every day. Ignore it, and you can easily be off by 10–16 minutes when you try to predict sun angles, especially for solar panel tracking or sunrise planning.

Applications in Solar Energy Systems

If you’re sizing a photovoltaic system, you need the incident angle to know how much sunlight your panels actually “see.” The direct beam strength is multiplied by the cosine of the angle between the sun’s rays and your panel. If sunlight hits at 60°, your output drops to half because cos(60°) = 0.5. Most panels are tilted close to the site latitude, aimed at the equator. That yields the best all-year average output. If you can adjust tilt seasonally, lean them a bit lower (latitude – 15°) in summer and higher (latitude + 15°) in winter to get a bump in output. Single-axis trackers follow the sun east-west and can give 20-30% more energy; dual-axis trackers (tilt and turn) grab 30-40% more, but you pay more for that hardware.

For concentrated solar power (CSP) setups, small errors in angle cost you a lot more. Parabolic troughs are sensitive to even a degree or two off the ideal angle, so trackers must stay within about 0.1° if you want full performance. For reference, at 35°N, the sun’s noon angle goes from just 31.5° in winter to 78.5° in summer. The farther from the equator, the bigger this swing, and the more you need to re-aim — or accept reduced performance in winter. That’s why big CSP plants are typically built in the 15°–40° latitude bands in both hemispheres.

Architectural Daylighting and Building Design

Passive solar building relies on knowing when and where sunlight will hit. For instance, south-facing windows at northern latitudes are built to catch more winter sun for free heat, but avoid overheating from high-angle summer sun. Overhangs above windows are sized using elevation angle calculations. For example, a 0.6m overhang on a 2m window fully shades the glass when the sun is above 16.7° elevation (arctan 0.6/2). It’ll block higher summer sun but admit lower winter sun — reducing unwanted heat. Commercial buildings now use daylighting controls that dial back artificial lights whenever measured and calculated sunlight is sufficient. A north-facing skylight at 45°N won’t see direct sun except for a few months around the summer solstice, so its output isn’t steady all year. Weather and local shading always matter, but geometry sets your starting point.

Daylighting controls often rely on predictions of sun position and its path, but real results also depend on building shadows, landscape, and cloud cover. Diffuse sky light acts differently from direct beam radiation and can sometimes matter just as much in northern and cloudy climates.

Agricultural and Ecological Applications

Calculating day length isn’t just for solar energy. Crops use changes in day length as cues to flower and set seed. Some require long days, others short. The difference in day length from winter to summer — 9.1 to 15.3 hours at 42°N, for example — is enough to affect crop timing and yields. Greenhouses often use these calculations to figure out how much extra lighting is needed (if any) at different times of year. They’ll manipulate the artificial light cycle to trigger crops to bloom out-of-season or on a production schedule.

Wildlife behavior also tracks these solar rhythms. Many animals are most active around dawn and dusk, when the sun’s elevation angle hits key thresholds (say, from -6° at civil twilight up to 0° at sunrise). If you need to predict migration, breeding, or foraging windows, you’ll be solving for the hour angles that set those sun elevation marks. Migrating birds time their movements to calendar cues like changing sunrise times — sun angles change more rapidly around the equinox, which signals some of these cycles. Even forest microclimates depend on sun exposure; slopes facing the equator may get enough extra heat to significantly change plant or animal populations compared to the opposite slope.

Worked Example: Solar Panel Performance Analysis

Problem: A fixed photovoltaic array in Denver, Colorado (latitude 39.7°N, longitude 104.9°W, Mountain Time Zone UTC-7, standard meridian 105°W) faces south with a tilt angle of 40° from horizontal. Calculate the incident angle and effective irradiance at 2:30 PM Mountain Standard Time on March 15 (day 74 of the year, near the vernal equinox). Assume direct normal irradiance (DNI) of 850 W/m².

Solution:

Step 1: Calculate solar declination for day 74
δ = 23.45° × sin[(360°/365) × (74 - 81)]
δ = 23.45° × sin[(360°/365) × (-7)]
δ = 23.45° × sin(-6.904°)
δ = 23.45° × (-0.1203)
δ = -2.82°

Step 2: Calculate Equation of Time for day 74
B = (360°/365) × (74 - 81) = -6.904°
EoT = 9.87 × sin(2 × (-6.904°)) - 7.53 × cos(-6.904°) - 1.5 × sin(-6.904°)
EoT = 9.87 × sin(-13.808°) - 7.53 × cos(-6.904°) - 1.5 × sin(-6.904°)
EoT = 9.87 × (-0.2387) - 7.53 × (0.9927) - 1.5 × (-0.1203)
EoT = -2.356 - 7.473 + 0.180
EoT = -9.65 minutes

Step 3: Convert standard time to solar time
Longitude correction = 4 min/degree × (104.9° - 105.0°) = 4 × (-0.1°) = -0.4 minutes
Total time correction TC = -0.4 min + (-9.65 min) = -10.05 minutes
Solar time = 14.5 hours - (10.05/60) hours = 14.5 - 0.1675 = 14.33 hours (2:20 PM solar time)

Step 4: Calculate hour angle
H = 15° × (14.33 - 12) = 15° × 2.33 = 34.95°

Step 5: Calculate solar elevation angle
sin(α) = sin(39.7°) × sin(-2.82°) + cos(39.7°) × cos(-2.82°) × cos(34.95°)
sin(α) = 0.6383 × (-0.0492) + 0.7698 × 0.9988 × 0.8192
sin(α) = -0.0314 + 0.6299
sin(α) = 0.5985
α = arcsin(0.5985) = 36.75°

Step 6: Calculate solar azimuth angle
cos(Az) = [sin(-2.82°) - sin(39.7°) × sin(36.75°)] / [cos(39.7°) × cos(36.75°)]
cos(Az) = [-0.0492 - 0.6383 × 0.5985] / [0.7698 × 0.7998]
cos(Az) = [-0.0492 - 0.3820] / 0.6156
cos(Az) = -0.4312 / 0.6156
cos(Az) = -0.7005
Az = arccos(-0.7005) = 134.5°
Since H = 34.95° (positive, afternoon), Az = 360° - 134.5° = 225.5° (southwest)

Step 7: Calculate incident angle on tilted surface
Surface tilt β = 40°, surface azimuth γ = 180° (south-facing)
cos(θ) = sin(36.75°) × cos(40°) + cos(36.75°) × sin(40°) × cos(225.5° - 180°)
cos(θ) = 0.5985 × 0.7660 + 0.8010 × 0.6428 × cos(45.5°)
cos(θ) = 0.4585 + 0.5150 × 0.7002
cos(θ) = 0.4585 + 0.3606
cos(θ) = 0.8191
θ = arccos(0.8191) = 34.95°

Step 8: Calculate effective irradiance on panel surface
Effective irradiance = DNI × cos(θ)
Effective irradiance = 850 W/m² × 0.8191
Effective irradiance = 696 W/m²

Result Summary: At 2:30 PM MST on March 15 in Denver, the sun elevation is 36.75°, azimuth 225.5°. The 40°-tilted, south-facing panel receives sunlight at a 34.95° angle of incidence, converting to 696 W/m² out of a possible 850 W/m² direct beam — 81.9% of maximum. That’s solid performance for a fixed tilt at this date and place, as the sun’s angle is still easily manageable for the panel geometry.

Limitations and Advanced Considerations

If you use these standard algorithms, you’ll generally be within half a degree for most engineering work. The model leaves out a few refinements. For example, atmospheric refraction lifts the sun by about 0.57° at the horizon — which can advance sunrise and delay sunset by 2–3 minutes at temperate latitudes. Parallax is so tiny for the sun (up to 0.003°), it only matters in high-precision astronomy. The equations assume a 365-day year, so for leap years (if you don’t fix the day number), declination can be off by about 0.25°.

Nutation and polar motion (small wobbles in Earth’s axis) change sun angles by a few arcseconds at most — only relevant for serious astronomical tracking or satellites. If you need sub-0.01° accuracy, use the full Solar Position Algorithm (SPA) from NREL, which covers a lot more corrections and gets uncertainties below 0.0003°. But for most engineering tasks (solar panel layouts, daylight design, rough ecological planning), the simpler method here is more than accurate enough, and way faster to calculate or check by hand. Understanding the pared-down geometry is also good for sanity-checking and troubleshooting — you’ll know what to expect before running simulations or buying hardware. Explore additional engineering calculators covering related atmospheric and environmental phenomena.

Frequently Asked Questions

Why does my location never experience the sun directly overhead? +

How does daylight saving time affect solar time calculations? +

What causes the Equation of Time to vary throughout the year? +

How do I optimize solar panel tilt angle for maximum annual energy? +

Why do polar regions experience midnight sun and polar night? +

How accurate are simplified solar position equations for engineering applications? +

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About the Author

Robbie Dickson — Chief Engineer & Founder, FIRGELLI Automations

Robbie Dickson brings over two decades of engineering expertise to FIRGELLI Automations. With a distinguished career at Rolls-Royce, BMW, and Ford, he has deep expertise in mechanical systems, actuator technology, and precision engineering.

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