Inverting Buck Boost Converter Interactive Calculator

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Generating a negative supply rail from a positive voltage source comes up all the time in real designs—battery-powered gear, automotive ECUs, and analog front-ends all run into this need. An inverting buck-boost is about as straightforward as it gets for this: a standard go-to if you want one DC rail of opposite polarity, no transformers, and you don't need bidirectional power flow. This Inverting Buck-Boost Converter Calculator lets you crunch the numbers for output voltage, duty cycle, inductor size, output current, required capacitor, and estimate losses and efficiency. The result depends on your inputs: switching frequency, desired ripple, MOSFET characteristics, and so on. In places like automotive or PLC modules, getting the value wrong means you might see instability, more ripple than expected, or real thermal problems. Below you'll find direct formulas, a sample design that's actually worked through, and some practical background on control, behavior, and what to watch for with the layout.

What is an Inverting Buck-Boost Converter?

An inverting buck-boost converter is a DC-DC circuit that takes in a positive voltage and spits out a negative one—bigger or smaller in magnitude, depending on how you run it. At the heart, it's just a switch and an inductor moving energy around: the controls and component choices steer where the output lands.

Simple Explanation

The inductor acts like a spring: close the switch, current ramps up and stores energy. Then open the switch and that stored energy dumps into the output, but the connection flips the voltage “backward” compared to ground—so you get negative output. Running the switch longer each cycle (higher duty cycle) jacks up the output magnitude. This slider gives you real control over the output.

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Circuit Diagram

Inverting Buck Boost Converter Interactive Calculator Technical Diagram

How to Use This Calculator

  1. Pick your calculation mode—find output voltage, duty cycle, inductor, output current, capacitor, or estimate losses/efficiency.
  2. Plug in your known quantities: input voltage, duty cycle or target output, output current, switching frequency, ripple current, or whatever fits your calculation mode.
  3. On the efficiency side, you’ll also want MOSFET resistance (RDS(on)), diode drop, inductor resistance, and inductance value.
  4. Hit Calculate. The result reflects what you entered. Garbage-in, garbage-out applies—double check your units and numbers.

Inverting Buck-Boost Converter Calculator

Volts (V)
Decimal (0-1)
Amperes (A)
Hertz (Hz)
Amperes (A)
Engineering calculation notice

This calculator is intended for education, concept evaluation, and preliminary design. Results are based on the equations and assumptions described on this page, but cannot account for every real-world load case, tolerance, material property, environmental condition, installation detail, safety factor, code, or regulatory requirement. Verify all inputs, assumptions, units, and results independently before selecting components or using the result in a real application. Safety-critical, structural, medical, lifting, transportation, or regulated applications must be reviewed by a qualified engineer.

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Inverting Buck-Boost Converter Interactive Visualizer

Here you can see how changing real component values or switching parameters affects waveforms, ripple, and output voltage. It’s a good way to spot what actually matters versus what looks important on a datasheet.

Input Voltage (Vin) 12 V
Duty Cycle (D) 0.50
Output Current (Iout) 1.0 A
Switching Freq (fsw) 100 kHz

OUTPUT VOLTAGE

-12.0 V

INDUCTOR VALUE

200 μH

OUTPUT CAP

100 μF

EFFICIENCY

87%

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Governing Equations

Output voltage, duty cycle, inductor minimum, and average/peak currents are all related by the classic inverting buck-boost formulas. Plug in only what you actually need—more variables just means more chance for a mistake.

Output Voltage

Vout = -Vin × (D / (1 - D))

Where:

Vout = Output voltage (V, negative polarity)

Vin = Input voltage (V, positive)

D = Duty cycle (0 to 1)

Reverse that if you want duty cycle from your target voltage instead.

Duty Cycle

D = |Vout| / (Vin + |Vout|)

Where:

|Vout| = Absolute value of output voltage (V)

Vin = Input voltage (V)

Inductor sizing matters for real ripple: target a ripple current you can live with, calculate L, and round up to the next E12 or E24 standard.

Inductor Value

L = Vin × D / (fsw × ΔIL)

Where:

L = Inductance (H)

fsw = Switching frequency (Hz)

ΔIL = Inductor current ripple (A)

For average and input currents, these formulas are what you’ll use for heat and wire size estimates.

Current Relationships

Iin = Iout × |Vout| / (Vin × (1 - D))

IL,avg = Iin / D

Where:

Iin = Average input current (A)

Iout = Output current (A)

IL,avg = Average inductor current (A)

Set your output capacitor to get ripple below your spec. Electrolytics or ceramics? Depends where your lowest ESR at switching frequency lands.

Output Capacitor

C = Iout × D / (fsw × ΔVout)

Where:

C = Output capacitance (F)

ΔVout = Output voltage ripple (V)

Simple Example

Let's make this concrete: Vin = 12 V, D = 0.5, Iout = 1 A, fsw = 100 kHz, ΔIL = 0.3 A.

Output: Vout = −12 × 0.5 / (1 − 0.5) = −12 V

Inductor: L = 12 × 0.5 / (100,000 × 0.3) = 200 μH

Cap (for 50 mV ripple): C = 1 × 0.5 / (100,000 × 0.05) = 100 μF

Theory & Practical Applications

Topology Fundamentals and Operating Principles

Here’s what’s really happening: when the MOSFET is on, the inductor gets hit with Vin, ramping current up linearly (dI/dt = Vin/L). Output cap supplies the load, diode is off. Turn off the switch, the inductor releases energy—the voltage across it flips, forward-biasing the diode and dumping energy to the output cap. Both input and output share ground at the switching node. You don't get needlessly isolated feedback, but you do need to manage ground bounce and watch for EMI issues in the layout. The output-to-input ratio is set by -D/(1-D); at high duty cycle, even a slight tweak gives a huge voltage shift—a real headache for control. If you push above D=0.75, expect trouble: efficiency dives, and keeping your loop stable takes more design work than most realize.

This circuit can both buck and boost, depending on where you run it: below D=0.5 you buck, above you boost (output voltage bigger in magnitude than input). Most stable and efficient designs for real loads stay around D=0.4–0.7. Control gets notably twitchy at the edges.

Continuous vs. Discontinuous Conduction Mode

Continuous conduction mode (CCM) means your inductor current never hits zero in a cycle. You can find the minimum inductance to stay in CCM using Lcrit = (1-D)²Rload/(2fsw). Drop below that and you're in discontinuous conduction (DCM)—different math, different control, and pretty different noise and loss profile. In DCM, output becomes load-dependent and you lose the right-half-plane zero (handy if you want stable fast loops, less so for efficiency). In real industry, a lot of designers pick DCM for light loads—think bias rails or where fast reversal or quick response is needed. You get simpler current limiting too, because peak current is just set by input voltage, on-time, and L. But plan for more noise and less efficiency in DCM—no free lunch.

For applications like gate drivers in automotive, DCM works fine—very little load, small inductors, high frequency. For high-current loads, CCM is still the smart bet unless you’re intentionally trading away efficiency for response.

Component Selection and Parasitic Effects

MOSFETs: pick a low-enough RDS(on) for conduction losses at your lowest frequency, but don’t ignore switching losses—these add up fast with high gate charge and output capacitance, especially above 200 kHz. RMS current through the switch scales with inductor current and duty cycle. Spikes from dI/dt add up fast, so snubbers (RC) are near mandatory if you want to avoid oscillations or turn-on failures, even at 12V—the values needed are usually modest, so oversized snubbers just waste power.

For the diode, check the forward drop—it’s a big chunk of losses at lower voltages. Standard Schottky diodes have 0.4-0.5V drops; SiC drops are lower but watch your BOM price. If you’re running more than 2A, consider synchronous rectification: it’s more parts (need dead-time control and better PCB layout), but can be a real help at higher currents to bring efficiency up several points.

Control Loop Dynamics and Compensation

The control is limited by the right-half-plane zero (RHP zero): that’s the frequency at which your feedback loop actually works against your efforts. The higher your duty cycle or smaller your load resistance, the worse this gets (the zero moves to lower frequency which chokes your allowable control bandwidth). Voltage mode is the most restricted; current mode kicks the zero up a bit, but you still need to budget phase margin. Modern controllers often try to tune compensation as operating point shifts (digital control helps), but you won’t get away from the RHP zero if you stay in CCM.

Real-World Applications Across Industries

You'll see these inverters everywhere in cars—negative rails for CAN or analog, LCD bias, and low-current reference supplies. Automotive standards like ISO 26262 like the “fail safe” behavior of DCM, where you can't over-current the output easily. High-frequency chips in cars use these to keep components small enough to fit available real estate. In industrial control (PLCs), you often get ±10V or ±12V rails from a single 24V supply, supporting both analog input and output channels to tight voltage specs. Here, the no-transformer approach cuts noise and cost, as long as your layout is quiet enough to not pick up EMI from the rest of the system.

Worked Example: Designing for Automotive LED Driver Application

Problem Statement: Want to supply -48V @ 250 mA to drive LEDs in an auto tail light from a 9–16V (typical automotive) input. What D-range, inductor, output cap, and efficiency can you expect? Assume you’re sticking close to the numbers: RDS(on)=0.065Ω, Vf=0.45V, RL=0.035Ω, switching at 400 kHz, 30% ripple allowed.

Duty Cycle Range: For the lowest input, Dmax = 48/(9+48) ≈ 0.84. For max input, Dmin = 48/64 = 0.75. The range is tight and high—control gets hard near D=0.8. If you can move away from 9V, life gets easier.

Inductor Sizing: Worst case is minimum input and highest current. Inductor current goes high—plan for almost 8.5A average and 2.5A ripple. Resulting inductor is about 7.5–8μH by formula, round to 8.2μH (E12). Peak current close to 10A—pick an inductor with plenty of margin (at least 12A rating), and keep DCR under 35mΩ or losses will add up.

Capacitor: With C = 0.21/40,000 = 5.26μF as the absolute minimum for math, you’ll want more in practice since capacitor ESR (equivalent series resistance) is a bigger part of your total ripple. A 22μF aluminum-poly with <0.3Ω ESR is a reasonable choice, providing both ripple and ESR margin, and bigger if you want less output noise.

Efficiency: Crunching the numbers (see detailed math steps above), total efficiency lands just above 85%. Most of your loss is in switch RDS(on) and the inductor's resistance. Synchronous rectification (using a second MOSFET) or a lower resistance main switch can get you a couple more percent, but with added complexity and cost, so decide what's worth it for your application.

Advanced Topics and Emerging Technologies

Multi-phase designs split current among several parallel converters, phase-shifting their clocks. This shrinks ripple currents and spreads out heat, so you can use smaller parts and get better overall efficiency in higher-power systems. Ideal for applications above 5A or so, but hard to justify for sub-amp rails unless you've got space and cost to burn.

GaN and SiC parts now make MHz-range switching practical, shrinking your passives even further. Just watch for massive increases in layout sensitivity: stray loop inductance quickly bites you with ringing or even EMI failures. If you're running above a few hundred kHz and care about board space or efficiency, four-layer boards and tight ground planes aren't optional anymore. You pay for these devices, though—for most, silicon still does the job at lower cost for standard duty cycles and currents.

For more calculator tools on other supply topologies, see the engineering calculator library.

Frequently Asked Questions

Why does the inverting buck-boost converter produce a negative output voltage? +

What causes the right-half-plane zero and how does it affect control loop design? +

How do I select between continuous and discontinuous conduction mode operation? +

What causes the input current discontinuity and how should it be addressed? +

Why does efficiency drop significantly at very high or very low duty cycles? +

What PCB layout practices are critical for reliable inverting buck-boost operation? +

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About the Author

Robbie Dickson — Chief Engineer & Founder, FIRGELLI Automations

Robbie Dickson brings over two decades of engineering expertise to FIRGELLI Automations. With a distinguished career at Rolls-Royce, BMW, and Ford, he has deep expertise in mechanical systems, actuator technology, and precision engineering.

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